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11304304413 = 33768101471
BaseRepresentation
bin10101000011100100…
…11111111100011101
31002011211001011102020
422201302133330131
5141122400220123
65105414250353
7550063000503
oct124162377435
932154034366
1011304304413
114880a92246
1222359569b9
1310b1ca172c
14793484673
1546264d7e3
hex2a1c9ff1d

11304304413 has 4 divisors (see below), whose sum is σ = 15072405888. Its totient is φ = 7536202940.

The previous prime is 11304304399. The next prime is 11304304421. The reversal of 11304304413 is 31440340311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11304304413 - 28 = 11304304157 is a prime.

It is a super-3 number, since 3×113043044133 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11304304433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1884050733 + ... + 1884050738.

It is an arithmetic number, because the mean of its divisors is an integer number (3768101472).

Almost surely, 211304304413 is an apocalyptic number.

It is an amenable number.

11304304413 is a deficient number, since it is larger than the sum of its proper divisors (3768101475).

11304304413 is an equidigital number, since it uses as much as digits as its factorization.

11304304413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3768101474.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 11304304413 its reverse (31440340311), we get a palindrome (42744644724).

The spelling of 11304304413 in words is "eleven billion, three hundred four million, three hundred four thousand, four hundred thirteen".

Divisors: 1 3 3768101471 11304304413