Base | Representation |
---|---|
bin | 1010010001111111110110… |
… | …0000011101010010111111 |
3 | 1111000200101221120002021002 |
4 | 2210133331200131102333 |
5 | 2440202212344200111 |
6 | 40013043532000515 |
7 | 2244465251306126 |
oct | 244377540352277 |
9 | 44020357502232 |
10 | 11304312100031 |
11 | 366914a528845 |
12 | 1326a2730013b |
13 | 63ccb871a832 |
14 | 2b11bb270abd |
15 | 1490b76dc63b |
hex | a47fd81d4bf |
11304312100031 has 2 divisors, whose sum is σ = 11304312100032. Its totient is φ = 11304312100030.
The previous prime is 11304312100027. The next prime is 11304312100063. The reversal of 11304312100031 is 13000121340311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11304312100031 - 22 = 11304312100027 is a prime.
It is a super-3 number, since 3×113043121000313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 11304312099976 and 11304312100012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11304312103031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652156050015 + 5652156050016.
It is an arithmetic number, because the mean of its divisors is an integer number (5652156050016).
Almost surely, 211304312100031 is an apocalyptic number.
11304312100031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11304312100031 is an equidigital number, since it uses as much as digits as its factorization.
11304312100031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11304312100031 its reverse (13000121340311), we get a palindrome (24304433440342).
The spelling of 11304312100031 in words is "eleven trillion, three hundred four billion, three hundred twelve million, one hundred thousand, thirty-one".
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