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11304312100127 is a prime number
BaseRepresentation
bin1010010001111111110110…
…0000011101010100011111
31111000200101221120002101122
42210133331200131110133
52440202212344201002
640013043532001155
72244465251306324
oct244377540352437
944020357502348
1011304312100127
11366914a528922
121326a273001bb
1363ccb871a8a7
142b11bb270b4b
151490b76dc6a2
hexa47fd81d51f

11304312100127 has 2 divisors, whose sum is σ = 11304312100128. Its totient is φ = 11304312100126.

The previous prime is 11304312100073. The next prime is 11304312100163. The reversal of 11304312100127 is 72100121340311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11304312100127 - 26 = 11304312100063 is a prime.

It is a super-3 number, since 3×113043121001273 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 11304312100096 and 11304312100105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11304312100177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652156050063 + 5652156050064.

It is an arithmetic number, because the mean of its divisors is an integer number (5652156050064).

Almost surely, 211304312100127 is an apocalyptic number.

11304312100127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11304312100127 is an equidigital number, since it uses as much as digits as its factorization.

11304312100127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 11304312100127 its reverse (72100121340311), we get a palindrome (83404433440438).

The spelling of 11304312100127 in words is "eleven trillion, three hundred four billion, three hundred twelve million, one hundred thousand, one hundred twenty-seven".