Base | Representation |
---|---|
bin | 1010010001111111110110… |
… | …0000011101010100100010 |
3 | 1111000200101221120002101202 |
4 | 2210133331200131110202 |
5 | 2440202212344201010 |
6 | 40013043532001202 |
7 | 2244465251306330 |
oct | 244377540352442 |
9 | 44020357502352 |
10 | 11304312100130 |
11 | 366914a528925 |
12 | 1326a27300202 |
13 | 63ccb871a8aa |
14 | 2b11bb270b50 |
15 | 1490b76dc6a5 |
hex | a47fd81d522 |
11304312100130 has 16 divisors (see below), whose sum is σ = 23254584891840. Its totient is φ = 3875764148592.
The previous prime is 11304312100127. The next prime is 11304312100163. The reversal of 11304312100130 is 3100121340311.
11304312100130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×113043121001303 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80745086360 + ... + 80745086499.
It is an arithmetic number, because the mean of its divisors is an integer number (1453411555740).
Almost surely, 211304312100130 is an apocalyptic number.
11304312100130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11304312100130 is an abundant number, since it is smaller than the sum of its proper divisors (11950272791710).
11304312100130 is a wasteful number, since it uses less digits than its factorization.
11304312100130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161490172873.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11304312100130 its reverse (3100121340311), we get a palindrome (14404433440441).
The spelling of 11304312100130 in words is "eleven trillion, three hundred four billion, three hundred twelve million, one hundred thousand, one hundred thirty".
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