11304413131 has 4 divisors (see below), whose sum is σ = 12332087064. Its totient is φ = 10276739200.

The previous prime is 11304413111. The next prime is 11304413161. The reversal of 11304413131 is 13131440311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13131440311 = 11 ⋅1193767301.

It is a cyclic number.

It is not a de Polignac number, because 11304413131 - 2²⁷ = 11170195403 is a prime.

It is a super-3 number, since 3×11304413131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (11304413111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513836950 + ... + 513836971.

It is an arithmetic number, because the mean of its divisors is an integer number (3083021766).

Almost surely, 2^11304413131 is an apocalyptic number.

11304413131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11304413131 is a deficient number, since it is larger than the sum of its proper divisors (1027673933).

11304413131 is a wasteful number, since it uses less digits than its factorization.

11304413131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1027673932.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11304413131 its reverse (13131440311), we get a palindrome (24435853442).

The spelling of 11304413131 in words is "eleven billion, three hundred four million, four hundred thirteen thousand, one hundred thirty-one".