Base | Representation |
---|---|
bin | 10101000011100101… |
… | …11010011111001110 |
3 | 1002011211020200112221 |
4 | 22201302322133032 |
5 | 141122412210014 |
6 | 5105420445554 |
7 | 550063632460 |
oct | 124162723716 |
9 | 32154220487 |
10 | 11304413134 |
11 | 48810569a3 |
12 | 22359a98ba |
13 | 10b200c071 |
14 | 7934b2130 |
15 | 462670b24 |
hex | 2a1cba7ce |
11304413134 has 16 divisors (see below), whose sum is σ = 19487260800. Its totient is φ = 4817681784.
The previous prime is 11304413111. The next prime is 11304413161. The reversal of 11304413134 is 43131440311.
It is a happy number.
It is a super-3 number, since 3×113044131343 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11304413099 and 11304413108.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2252964 + ... + 2257975.
It is an arithmetic number, because the mean of its divisors is an integer number (1217953800).
Almost surely, 211304413134 is an apocalyptic number.
11304413134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
11304413134 is a deficient number, since it is larger than the sum of its proper divisors (8182847666).
11304413134 is a wasteful number, since it uses less digits than its factorization.
11304413134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4511127.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11304413134 its reverse (43131440311), we get a palindrome (54435853445).
The spelling of 11304413134 in words is "eleven billion, three hundred four million, four hundred thirteen thousand, one hundred thirty-four".
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