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1130524405033 is a prime number
BaseRepresentation
bin10000011100111000100…
…000010110110100101001
311000002002012010012120111
4100130320200112310221
5122010303221430113
62223204501254321
7144451306614022
oct20347040266451
94002065105514
101130524405033
113a64a8610311
1216312a4043a1
13827b99bb8ba
143ca0941bc49
151e61a66413d
hex10738816d29

1130524405033 has 2 divisors, whose sum is σ = 1130524405034. Its totient is φ = 1130524405032.

The previous prime is 1130524405027. The next prime is 1130524405067. The reversal of 1130524405033 is 3305044250311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1025514706329 + 105009698704 = 1012677^2 + 324052^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130524405033 - 229 = 1129987534121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1130524404986 and 1130524405004.

It is not a weakly prime, because it can be changed into another prime (1130524405333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565262202516 + 565262202517.

It is an arithmetic number, because the mean of its divisors is an integer number (565262202517).

Almost surely, 21130524405033 is an apocalyptic number.

It is an amenable number.

1130524405033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130524405033 is an equidigital number, since it uses as much as digits as its factorization.

1130524405033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 1130524405033 its reverse (3305044250311), we get a palindrome (4435568655344).

The spelling of 1130524405033 in words is "one trillion, one hundred thirty billion, five hundred twenty-four million, four hundred five thousand, thirty-three".