Base | Representation |
---|---|
bin | 110100101001001111… |
… | …1110110010001000111 |
3 | 101210210212121010202021 |
4 | 1221102133312101013 |
5 | 3323013111331101 |
6 | 123534055024011 |
7 | 11111364413041 |
oct | 1512237662107 |
9 | 353725533667 |
10 | 113053230151 |
11 | 43a44668114 |
12 | 19ab136b007 |
13 | a878c2ab74 |
14 | 56868c4a91 |
15 | 2e1a1a35a1 |
hex | 1a527f6447 |
113053230151 has 4 divisors (see below), whose sum is σ = 113115246912. Its totient is φ = 112991213392.
The previous prime is 113053230079. The next prime is 113053230179. The reversal of 113053230151 is 151032350311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113053230151 - 223 = 113044841543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113053230181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31005646 + ... + 31009291.
It is an arithmetic number, because the mean of its divisors is an integer number (28278811728).
Almost surely, 2113053230151 is an apocalyptic number.
113053230151 is a deficient number, since it is larger than the sum of its proper divisors (62016761).
113053230151 is an equidigital number, since it uses as much as digits as its factorization.
113053230151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62016760.
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 113053230151 its reverse (151032350311), we get a palindrome (264085580462).
The spelling of 113053230151 in words is "one hundred thirteen billion, fifty-three million, two hundred thirty thousand, one hundred fifty-one".
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