Base | Representation |
---|---|
bin | 1010010010000100011001… |
… | …0111010000100110011111 |
3 | 1111000210120010120122120212 |
4 | 2210201012113100212133 |
5 | 2440212213303104003 |
6 | 40013405114403035 |
7 | 2244540453020213 |
oct | 244410627204637 |
9 | 44023503518525 |
10 | 11305534425503 |
11 | 36697174a2a8a |
12 | 132710873047b |
13 | 640151a2aa46 |
14 | 2b1295732943 |
15 | 149139b87dd8 |
hex | a48465d099f |
11305534425503 has 8 divisors (see below), whose sum is σ = 11609868204480. Its totient is φ = 11003858583840.
The previous prime is 11305534425473. The next prime is 11305534425569. The reversal of 11305534425503 is 30552443550311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11305534425503 - 28 = 11305534425247 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11305534445503) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 664475708 + ... + 664492721.
It is an arithmetic number, because the mean of its divisors is an integer number (1451233525560).
Almost surely, 211305534425503 is an apocalyptic number.
11305534425503 is a deficient number, since it is larger than the sum of its proper divisors (304333778977).
11305534425503 is a wasteful number, since it uses less digits than its factorization.
11305534425503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1328968657.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 11305534425503 its reverse (30552443550311), we get a palindrome (41857977975814).
The spelling of 11305534425503 in words is "eleven trillion, three hundred five billion, five hundred thirty-four million, four hundred twenty-five thousand, five hundred three".
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