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1130613433 is a prime number
BaseRepresentation
bin100001101100011…
…1100101010111001
32220210110010001121
41003120330222321
54303414112213
6304104545241
740006025035
oct10330745271
92823403047
101130613433
11530224674
12276782221
1315030bc41
14aa22b1c5
15693d188d
hex4363cab9

1130613433 has 2 divisors, whose sum is σ = 1130613434. Its totient is φ = 1130613432.

The previous prime is 1130613427. The next prime is 1130613479. The reversal of 1130613433 is 3343160311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1072366009 + 58247424 = 32747^2 + 7632^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130613433 - 29 = 1130612921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1130613398 and 1130613407.

It is not a weakly prime, because it can be changed into another prime (1130613413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565306716 + 565306717.

It is an arithmetic number, because the mean of its divisors is an integer number (565306717).

Almost surely, 21130613433 is an apocalyptic number.

It is an amenable number.

1130613433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130613433 is an equidigital number, since it uses as much as digits as its factorization.

1130613433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

The square root of 1130613433 is about 33624.5956555614. The cubic root of 1130613433 is about 1041.7688810319.

Adding to 1130613433 its reverse (3343160311), we get a palindrome (4473773744).

The spelling of 1130613433 in words is "one billion, one hundred thirty million, six hundred thirteen thousand, four hundred thirty-three".