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1130674351397 = 7431521768979
BaseRepresentation
bin10000011101000001011…
…100010110110100100101
311000002110122021021022112
4100131001130112310211
5122011110113221042
62223231415210405
7144455110261313
oct20350134266445
94002418237275
101130674351397
113a6575216228
12163170676a05
1382811a9c266
143ca212d10b3
151e6288d2982
hex10741716d25

1130674351397 has 4 divisors (see below), whose sum is σ = 1132196121120. Its totient is φ = 1129152581676.

The previous prime is 1130674351369. The next prime is 1130674351399. The reversal of 1130674351397 is 7931534760311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1130674351397 - 212 = 1130674347301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130674351399) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 760883747 + ... + 760885232.

It is an arithmetic number, because the mean of its divisors is an integer number (283049030280).

Almost surely, 21130674351397 is an apocalyptic number.

It is an amenable number.

1130674351397 is a deficient number, since it is larger than the sum of its proper divisors (1521769723).

1130674351397 is an equidigital number, since it uses as much as digits as its factorization.

1130674351397 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1521769722.

The product of its (nonzero) digits is 1428840, while the sum is 50.

The spelling of 1130674351397 in words is "one trillion, one hundred thirty billion, six hundred seventy-four million, three hundred fifty-one thousand, three hundred ninety-seven".

Divisors: 1 743 1521768979 1130674351397