Base | Representation |
---|---|
bin | 10101000100010000… |
… | …10001101011110011 |
3 | 1002012012210012100201 |
4 | 22202020101223303 |
5 | 141130330410141 |
6 | 5110140500031 |
7 | 550162345222 |
oct | 124210215363 |
9 | 32165705321 |
10 | 11310013171 |
11 | 4884231326 |
12 | 223784a617 |
13 | 10b321ccb2 |
14 | 79412ccb9 |
15 | 462dca031 |
hex | 2a2211af3 |
11310013171 has 2 divisors, whose sum is σ = 11310013172. Its totient is φ = 11310013170.
The previous prime is 11310013133. The next prime is 11310013199. The reversal of 11310013171 is 17131001311.
It is a strong prime.
It is an emirp because it is prime and its reverse (17131001311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11310013171 - 221 = 11307916019 is a prime.
It is not a weakly prime, because it can be changed into another prime (11310013471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655006585 + 5655006586.
It is an arithmetic number, because the mean of its divisors is an integer number (5655006586).
Almost surely, 211310013171 is an apocalyptic number.
11310013171 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310013171 is an equidigital number, since it uses as much as digits as its factorization.
11310013171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63, while the sum is 19.
Adding to 11310013171 its reverse (17131001311), we get a palindrome (28441014482).
The spelling of 11310013171 in words is "eleven billion, three hundred ten million, thirteen thousand, one hundred seventy-one".
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