Base | Representation |
---|---|
bin | 110100101010101001… |
… | …1011100110110101001 |
3 | 101210221011012010212121 |
4 | 1221111103130312221 |
5 | 3323112134440402 |
6 | 123542500111241 |
7 | 11112505534612 |
oct | 1512523346651 |
9 | 353834163777 |
10 | 113100311977 |
11 | 43a691a5414 |
12 | 19b05095521 |
13 | a885903c33 |
14 | 568cc5cc09 |
15 | 2e1e3a3837 |
hex | 1a554dcda9 |
113100311977 has 2 divisors, whose sum is σ = 113100311978. Its totient is φ = 113100311976.
The previous prime is 113100311971. The next prime is 113100311983. The reversal of 113100311977 is 779113001311.
It is a balanced prime because it is at equal distance from previous prime (113100311971) and next prime (113100311983).
It can be written as a sum of positive squares in only one way, i.e., 101003831721 + 12096480256 = 317811^2 + 109984^2 .
It is an emirp because it is prime and its reverse (779113001311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113100311977 is a prime.
It is not a weakly prime, because it can be changed into another prime (113100311971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550155988 + 56550155989.
It is an arithmetic number, because the mean of its divisors is an integer number (56550155989).
Almost surely, 2113100311977 is an apocalyptic number.
It is an amenable number.
113100311977 is a deficient number, since it is larger than the sum of its proper divisors (1).
113100311977 is an equidigital number, since it uses as much as digits as its factorization.
113100311977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3969, while the sum is 34.
The spelling of 113100311977 in words is "one hundred thirteen billion, one hundred million, three hundred eleven thousand, nine hundred seventy-seven".
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