11310033132121 has 4 divisors (see below), whose sum is σ = 11310041232000. Its totient is φ = 11310025032244.

The previous prime is 11310033132071. The next prime is 11310033132137. The reversal of 11310033132121 is 12123133001311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11310033132121 - 2³⁷ = 11172594178649 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11310033132092 and 11310033132101.

It is not an unprimeable number, because it can be changed into a prime (11310033138121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1359841 + ... + 4946638.

It is an arithmetic number, because the mean of its divisors is an integer number (2827510308000).

Almost surely, 2^{11310033132121} is an apocalyptic number.

It is an amenable number.

11310033132121 is a deficient number, since it is larger than the sum of its proper divisors (8099879).

11310033132121 is an equidigital number, since it uses as much as digits as its factorization.

11310033132121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8099878.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 11310033132121 its reverse (12123133001311), we get a palindrome (23433166133432).

The spelling of 11310033132121 in words is "eleven trillion, three hundred ten billion, thirty-three million, one hundred thirty-two thousand, one hundred twenty-one".