1131011013001 has 4 divisors (see below), whose sum is σ = 1131513463504. Its totient is φ = 1130508562500.

The previous prime is 1131011012939. The next prime is 1131011013007. The reversal of 1131011013001 is 1003101101311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1131011013001 - 2¹⁷ = 1131010881929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131011013007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251221875 + ... + 251226376.

It is an arithmetic number, because the mean of its divisors is an integer number (282878365876).

Almost surely, 2^{1131011013001} is an apocalyptic number.

It is an amenable number.

1131011013001 is a deficient number, since it is larger than the sum of its proper divisors (502450503).

1131011013001 is an equidigital number, since it uses as much as digits as its factorization.

1131011013001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 502450502.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 1131011013001 its reverse (1003101101311), we get a palindrome (2134112114312).

The spelling of 1131011013001 in words is "one trillion, one hundred thirty-one billion, eleven million, thirteen thousand, one".