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1131011023003 = 9623117532061
BaseRepresentation
bin10000011101010101100…
…000101010000010011011
311000010100002202221221021
4100131111200222002123
5122012302310214003
62223325043223311
7144466336034221
oct20352540520233
94003302687837
101131011023003
113a6728267624
12163245377b37
1382866769924
143ca53cccb11
151e6482372bd
hex1075582a09b

1131011023003 has 4 divisors (see below), whose sum is σ = 1131128564688. Its totient is φ = 1130893481320.

The previous prime is 1131011022997. The next prime is 1131011023007. The reversal of 1131011023003 is 3003201101311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131011023003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131011023007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58756408 + ... + 58775653.

It is an arithmetic number, because the mean of its divisors is an integer number (282782141172).

Almost surely, 21131011023003 is an apocalyptic number.

1131011023003 is a deficient number, since it is larger than the sum of its proper divisors (117541685).

1131011023003 is an equidigital number, since it uses as much as digits as its factorization.

1131011023003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117541684.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1131011023003 its reverse (3003201101311), we get a palindrome (4134212124314).

The spelling of 1131011023003 in words is "one trillion, one hundred thirty-one billion, eleven million, twenty-three thousand, three".

Divisors: 1 9623 117532061 1131011023003