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1131012017 is a prime number
BaseRepresentation
bin100001101101001…
…1101111110110001
32220211012100210222
41003122131332301
54304014341032
6304121302425
740012305062
oct10332357661
92824170728
101131012017
11530477083
12276934a15
1315041b4a5
14aa2d2569
156945ea12
hex4369dfb1

1131012017 has 2 divisors, whose sum is σ = 1131012018. Its totient is φ = 1131012016.

The previous prime is 1131012011. The next prime is 1131012053. The reversal of 1131012017 is 7102101311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1077414976 + 53597041 = 32824^2 + 7321^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131012017 - 224 = 1114234801 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131011986 and 1131012004.

It is not a weakly prime, because it can be changed into another prime (1131012011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565506008 + 565506009.

It is an arithmetic number, because the mean of its divisors is an integer number (565506009).

Almost surely, 21131012017 is an apocalyptic number.

It is an amenable number.

1131012017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131012017 is an equidigital number, since it uses as much as digits as its factorization.

1131012017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 42, while the sum is 17.

The square root of 1131012017 is about 33630.5221041839. The cubic root of 1131012017 is about 1041.8912876270.

Adding to 1131012017 its reverse (7102101311), we get a palindrome (8233113328).

The spelling of 1131012017 in words is "one billion, one hundred thirty-one million, twelve thousand, seventeen".