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1131012142301 is a prime number
BaseRepresentation
bin10000011101010101100…
…100111011010011011101
311000010100011212211022202
4100131111210323103131
5122012303102023201
62223325123221245
7144466351405406
oct20352544732335
94003304784282
101131012142301
113a6728961568
12163245817825
1382866a6c232
143ca541009ad
151e6483a8c6b
hex1075593b4dd

1131012142301 has 2 divisors, whose sum is σ = 1131012142302. Its totient is φ = 1131012142300.

The previous prime is 1131012142261. The next prime is 1131012142327. The reversal of 1131012142301 is 1032412101311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1030316352025 + 100695790276 = 1015045^2 + 317326^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131012142301 - 226 = 1130945033437 is a prime.

It is a super-3 number, since 3×11310121423013 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131012142501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565506071150 + 565506071151.

It is an arithmetic number, because the mean of its divisors is an integer number (565506071151).

Almost surely, 21131012142301 is an apocalyptic number.

It is an amenable number.

1131012142301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131012142301 is an equidigital number, since it uses as much as digits as its factorization.

1131012142301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1131012142301 its reverse (1032412101311), we get a palindrome (2163424243612).

The spelling of 1131012142301 in words is "one trillion, one hundred thirty-one billion, twelve million, one hundred forty-two thousand, three hundred one".