Base | Representation |
---|---|
bin | 110100101010101011… |
… | …0111010100100100011 |
3 | 101210221012220021121221 |
4 | 1221111112322210203 |
5 | 3323112403021011 |
6 | 123542531355511 |
7 | 11112516336364 |
oct | 1512526724443 |
9 | 353835807557 |
10 | 113101220131 |
11 | 43a69765759 |
12 | 19b05452b97 |
13 | a885b613c3 |
14 | 568d017b6b |
15 | 2e1e4d2971 |
hex | 1a555ba923 |
113101220131 has 2 divisors, whose sum is σ = 113101220132. Its totient is φ = 113101220130.
The previous prime is 113101220123. The next prime is 113101220137. The reversal of 113101220131 is 131022101311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113101220131 - 23 = 113101220123 is a prime.
It is a super-3 number, since 3×1131012201313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (113101220137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550610065 + 56550610066.
It is an arithmetic number, because the mean of its divisors is an integer number (56550610066).
Almost surely, 2113101220131 is an apocalyptic number.
113101220131 is a deficient number, since it is larger than the sum of its proper divisors (1).
113101220131 is an equidigital number, since it uses as much as digits as its factorization.
113101220131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 113101220131 its reverse (131022101311), we get a palindrome (244123321442).
The spelling of 113101220131 in words is "one hundred thirteen billion, one hundred one million, two hundred twenty thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •