Base | Representation |
---|---|
bin | 10000011101010101100… |
… | …101111111011100011011 |
3 | 11000010100012102000011212 |
4 | 100131111211333130123 |
5 | 122012303134441103 |
6 | 2223325133213335 |
7 | 144466353650204 |
oct | 20352545773433 |
9 | 4003305360155 |
10 | 1131012421403 |
11 | 3a6729032227 |
12 | 16324593124b |
13 | 82866b39297 |
14 | 3ca541745ab |
15 | 1e6484117d8 |
hex | 1075597f71b |
1131012421403 has 4 divisors (see below), whose sum is σ = 1147893203880. Its totient is φ = 1114131638928.
The previous prime is 1131012421387. The next prime is 1131012421411. The reversal of 1131012421403 is 3041242101311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1131012421403 - 24 = 1131012421387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1131012421103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8440391138 + ... + 8440391271.
It is an arithmetic number, because the mean of its divisors is an integer number (286973300970).
Almost surely, 21131012421403 is an apocalyptic number.
1131012421403 is a deficient number, since it is larger than the sum of its proper divisors (16880782477).
1131012421403 is an equidigital number, since it uses as much as digits as its factorization.
1131012421403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16880782476.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1131012421403 its reverse (3041242101311), we get a palindrome (4172254522714).
The spelling of 1131012421403 in words is "one trillion, one hundred thirty-one billion, twelve million, four hundred twenty-one thousand, four hundred three".
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