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11310132319987 is a prime number
BaseRepresentation
bin1010010010010101100001…
…1010110101011011110011
31111001020102120022220002011
42210211120122311123303
52440301122333214422
640015445243303351
72245062423333334
oct244453032653363
944036376286064
1011310132319987
113670666927186
121327b9051ab57
1364070548b877
142b15b024228b
15149308662077
hexa49586b56f3

11310132319987 has 2 divisors, whose sum is σ = 11310132319988. Its totient is φ = 11310132319986.

The previous prime is 11310132319961. The next prime is 11310132320057. The reversal of 11310132319987 is 78991323101311.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11310132319987 is a prime.

It is a super-2 number, since 2×113101323199872 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11310132319987.

It is not a weakly prime, because it can be changed into another prime (11310132319487) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655066159993 + 5655066159994.

It is an arithmetic number, because the mean of its divisors is an integer number (5655066159994).

Almost surely, 211310132319987 is an apocalyptic number.

11310132319987 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310132319987 is an equidigital number, since it uses as much as digits as its factorization.

11310132319987 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 244944, while the sum is 49.

The spelling of 11310132319987 in words is "eleven trillion, three hundred ten billion, one hundred thirty-two million, three hundred nineteen thousand, nine hundred eighty-seven".