Base | Representation |
---|---|
bin | 10101000100010001… |
… | …01110111101101110 |
3 | 1002012020000021212121 |
4 | 22202020232331232 |
5 | 141130343224402 |
6 | 5110143223154 |
7 | 550163354662 |
oct | 124210567556 |
9 | 32166007777 |
10 | 11310133102 |
11 | 4884303444 |
12 | 22378a7aba |
13 | 10b3262768 |
14 | 7941608a2 |
15 | 462e00837 |
hex | 2a222ef6e |
11310133102 has 4 divisors (see below), whose sum is σ = 16965199656. Its totient is φ = 5655066550.
The previous prime is 11310133069. The next prime is 11310133129. The reversal of 11310133102 is 20133101311.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×113101331022 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2827533274 + ... + 2827533277.
It is an arithmetic number, because the mean of its divisors is an integer number (4241299914).
Almost surely, 211310133102 is an apocalyptic number.
11310133102 is a deficient number, since it is larger than the sum of its proper divisors (5655066554).
11310133102 is an equidigital number, since it uses as much as digits as its factorization.
11310133102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5655066553.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11310133102 its reverse (20133101311), we get a palindrome (31443234413).
The spelling of 11310133102 in words is "eleven billion, three hundred ten million, one hundred thirty-three thousand, one hundred two".
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