Base | Representation |
---|---|
bin | 10000011101010101101… |
… | …001011000011101011111 |
3 | 11000010100021002011112002 |
4 | 100131111221120131133 |
5 | 122012303401412203 |
6 | 2223325204232515 |
7 | 144466364341562 |
oct | 20352551303537 |
9 | 4003307064462 |
10 | 1131013310303 |
11 | 3a672958a058 |
12 | 16324609b73b |
13 | 8286708aa66 |
14 | 3ca543264d9 |
15 | 1e648539d88 |
hex | 10755a5875f |
1131013310303 has 2 divisors, whose sum is σ = 1131013310304. Its totient is φ = 1131013310302.
The previous prime is 1131013310281. The next prime is 1131013310309. The reversal of 1131013310303 is 3030133101311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131013310303 - 26 = 1131013310239 is a prime.
It is a super-2 number, since 2×11310133103032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131013310309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565506655151 + 565506655152.
It is an arithmetic number, because the mean of its divisors is an integer number (565506655152).
Almost surely, 21131013310303 is an apocalyptic number.
1131013310303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131013310303 is an equidigital number, since it uses as much as digits as its factorization.
1131013310303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 1131013310303 its reverse (3030133101311), we get a palindrome (4161146411614).
The spelling of 1131013310303 in words is "one trillion, one hundred thirty-one billion, thirteen million, three hundred ten thousand, three hundred three".
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