Base | Representation |
---|---|
bin | 1010010010010101110010… |
… | …0001100001010001000001 |
3 | 1111001020121100220101222021 |
4 | 2210211130201201101001 |
5 | 2440301243000244444 |
6 | 40015500143241441 |
7 | 2245064220545125 |
oct | 244453441412101 |
9 | 44036540811867 |
10 | 11310201181249 |
11 | 36706a178a713 |
12 | 1327bab5a9281 |
13 | 64071681bc89 |
14 | 2b15b9449585 |
15 | 14930e715584 |
hex | a495c861441 |
11310201181249 has 2 divisors, whose sum is σ = 11310201181250. Its totient is φ = 11310201181248.
The previous prime is 11310201181217. The next prime is 11310201181283. The reversal of 11310201181249 is 94218110201311.
It is an a-pointer prime, because the next prime (11310201181283) can be obtained adding 11310201181249 to its sum of digits (34).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10087865299600 + 1222335881649 = 3176140^2 + 1105593^2 .
It is a cyclic number.
It is not a de Polignac number, because 11310201181249 - 25 = 11310201181217 is a prime.
It is a super-3 number, since 3×113102011812493 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11310201181289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655100590624 + 5655100590625.
It is an arithmetic number, because the mean of its divisors is an integer number (5655100590625).
Almost surely, 211310201181249 is an apocalyptic number.
It is an amenable number.
11310201181249 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310201181249 is an equidigital number, since it uses as much as digits as its factorization.
11310201181249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 34.
The spelling of 11310201181249 in words is "eleven trillion, three hundred ten billion, two hundred one million, one hundred eighty-one thousand, two hundred forty-nine".
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