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1131021301411 = 2863139503381
BaseRepresentation
bin10000011101010110000…
…111110111011010100011
311000010100211010011021001
4100131112013313122203
5122012312423121121
62223330051412431
7144466522303351
oct20352607673243
94003324104231
101131021301411
113a6733047981
121632488b4117
1382868928121
143ca554067d1
151e6490b7991
hex107561f76a3

1131021301411 has 4 divisors (see below), whose sum is σ = 1131060833424. Its totient is φ = 1130981769400.

The previous prime is 1131021301387. The next prime is 1131021301451. The reversal of 1131021301411 is 1141031201311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131021301411 is a prime.

It is a super-2 number, since 2×11310213014112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131021301451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19723060 + ... + 19780321.

It is an arithmetic number, because the mean of its divisors is an integer number (282765208356).

Almost surely, 21131021301411 is an apocalyptic number.

1131021301411 is a deficient number, since it is larger than the sum of its proper divisors (39532013).

1131021301411 is an equidigital number, since it uses as much as digits as its factorization.

1131021301411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39532012.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1131021301411 its reverse (1141031201311), we get a palindrome (2272052502722).

The spelling of 1131021301411 in words is "one trillion, one hundred thirty-one billion, twenty-one million, three hundred one thousand, four hundred eleven".

Divisors: 1 28631 39503381 1131021301411