113102131423 has 4 divisors (see below), whose sum is σ = 113112338328. Its totient is φ = 113091924520.

The previous prime is 113102131399. The next prime is 113102131433. The reversal of 113102131423 is 324131201311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 324131201311 = 61 ⋅5313626251.

It is a cyclic number.

It is not a de Polignac number, because 113102131423 - 2²⁵ = 113068576991 is a prime.

It is a super-3 number, since 3×113102131423³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113102131394 and 113102131403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113102131433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5086813 + ... + 5108998.

It is an arithmetic number, because the mean of its divisors is an integer number (28278084582).

Almost surely, 2^113102131423 is an apocalyptic number.

113102131423 is a deficient number, since it is larger than the sum of its proper divisors (10206905).

113102131423 is a wasteful number, since it uses less digits than its factorization.

113102131423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10206904.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 113102131423 its reverse (324131201311), we get a palindrome (437233332734).

The spelling of 113102131423 in words is "one hundred thirteen billion, one hundred two million, one hundred thirty-one thousand, four hundred twenty-three".