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11310213232303 = 52801321420331
BaseRepresentation
bin1010010010010101110100…
…1111011111011010101111
31111001020122012120122220121
42210211131033133122233
52440301304041413203
640015501253425411
72245064425146316
oct244453517373257
944036565518817
1011310213232303
1136706a8570867
121327bb363b267
1364071917b28b
142b15baca527d
151493107e60bd
hexa495d3df6af

11310213232303 has 4 divisors (see below), whose sum is σ = 11310235180648. Its totient is φ = 11310191283960.

The previous prime is 11310213232289. The next prime is 11310213232321. The reversal of 11310213232303 is 30323231201311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11310213232303 - 213 = 11310213224111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11310213232403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10182153 + ... + 11238178.

It is an arithmetic number, because the mean of its divisors is an integer number (2827558795162).

Almost surely, 211310213232303 is an apocalyptic number.

11310213232303 is a deficient number, since it is larger than the sum of its proper divisors (21948345).

11310213232303 is an equidigital number, since it uses as much as digits as its factorization.

11310213232303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21948344.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11310213232303 its reverse (30323231201311), we get a palindrome (41633444433614).

The spelling of 11310213232303 in words is "eleven trillion, three hundred ten billion, two hundred thirteen million, two hundred thirty-two thousand, three hundred three".

Divisors: 1 528013 21420331 11310213232303