Base | Representation |
---|---|
bin | 10000011101010110001… |
… | …011000100101111011111 |
3 | 11000010100212200212220221 |
4 | 100131112023010233133 |
5 | 122012313132024211 |
6 | 2223330121422211 |
7 | 144466532405326 |
oct | 20352613045737 |
9 | 4003325625827 |
10 | 1131022142431 |
11 | 3a6733571835 |
12 | 16324903a967 |
13 | 82868b60b7c |
14 | 3ca555850bd |
15 | 1e6491d1c71 |
hex | 107562c4bdf |
1131022142431 has 2 divisors, whose sum is σ = 1131022142432. Its totient is φ = 1131022142430.
The previous prime is 1131022142423. The next prime is 1131022142443. The reversal of 1131022142431 is 1342412201311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1131022142431 - 23 = 1131022142423 is a prime.
It is a super-2 number, since 2×11310221424312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131022142396 and 1131022142405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131022142491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565511071215 + 565511071216.
It is an arithmetic number, because the mean of its divisors is an integer number (565511071216).
Almost surely, 21131022142431 is an apocalyptic number.
1131022142431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131022142431 is an equidigital number, since it uses as much as digits as its factorization.
1131022142431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1131022142431 its reverse (1342412201311), we get a palindrome (2473434343742).
The spelling of 1131022142431 in words is "one trillion, one hundred thirty-one billion, twenty-two million, one hundred forty-two thousand, four hundred thirty-one".
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