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1131022201307 = 4925322963519
BaseRepresentation
bin10000011101010110001…
…011010011000111011011
311000010100212210212200112
4100131112023103013123
5122012313140420212
62223330122554535
7144466533042065
oct20352613230733
94003325725615
101131022201307
113a6733601a99
12163249068a4b
1382868b818cb
143ca5559c735
151e6491e4422
hex107562d31db

1131022201307 has 4 divisors (see below), whose sum is σ = 1131045214080. Its totient is φ = 1130999188536.

The previous prime is 1131022201303. The next prime is 1131022201333. The reversal of 1131022201307 is 7031022201311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131022201307 - 22 = 1131022201303 is a prime.

It is a super-2 number, since 2×11310222013072 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131022201303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11432507 + ... + 11531012.

It is an arithmetic number, because the mean of its divisors is an integer number (282761303520).

Almost surely, 21131022201307 is an apocalyptic number.

1131022201307 is a deficient number, since it is larger than the sum of its proper divisors (23012773).

1131022201307 is an equidigital number, since it uses as much as digits as its factorization.

1131022201307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23012772.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1131022201307 its reverse (7031022201311), we get a palindrome (8162044402618).

The spelling of 1131022201307 in words is "one trillion, one hundred thirty-one billion, twenty-two million, two hundred one thousand, three hundred seven".

Divisors: 1 49253 22963519 1131022201307