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113102551 = 211353527
BaseRepresentation
bin1101011110111…
…00111011010111
321212211012112101
412233130323113
5212423240201
615120102531
72542233022
oct657347327
9255735471
10113102551
1158930691
1231a64a47
131a5805b3
14110421b9
159de1d01
hex6bdced7

113102551 has 4 divisors (see below), whose sum is σ = 113158192. Its totient is φ = 113046912.

The previous prime is 113102543. The next prime is 113102557. The reversal of 113102551 is 155201311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113102551 - 23 = 113102543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113102557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24651 + ... + 28876.

It is an arithmetic number, because the mean of its divisors is an integer number (28289548).

Almost surely, 2113102551 is an apocalyptic number.

113102551 is a deficient number, since it is larger than the sum of its proper divisors (55641).

113102551 is an equidigital number, since it uses as much as digits as its factorization.

113102551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55640.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 113102551 is about 10634.9683121296. The cubic root of 113102551 is about 483.6050197732.

Adding to 113102551 its reverse (155201311), we get a palindrome (268303862).

It can be divided in two parts, 11310 and 2551, that added together give a triangular number (13861 = T166).

The spelling of 113102551 in words is "one hundred thirteen million, one hundred two thousand, five hundred fifty-one".

Divisors: 1 2113 53527 113102551