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113103002301 = 359976587629
BaseRepresentation
bin110100101010101110…
…1101101101010111101
3101210221100020211022020
41221111131231222331
53323113332033201
6123543033510353
711112540441252
oct1512535555275
9353840224266
10113103002301
1143a6a772723
1219b05b723b9
13a886336643
14568d35d429
152e1e735a36
hex1a5576dabd

113103002301 has 16 divisors (see below), whose sum is σ = 154941057600. Its totient is φ = 73359825408.

The previous prime is 113103002293. The next prime is 113103002351. The reversal of 113103002301 is 103200301311.

It is not a de Polignac number, because 113103002301 - 23 = 113103002293 is a prime.

It is a super-2 number, since 2×1131030023012 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113103002351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3276646 + ... + 3310983.

It is an arithmetic number, because the mean of its divisors is an integer number (9683816100).

Almost surely, 2113103002301 is an apocalyptic number.

It is an amenable number.

113103002301 is a deficient number, since it is larger than the sum of its proper divisors (41838055299).

113103002301 is an equidigital number, since it uses as much as digits as its factorization.

113103002301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6587788.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 113103002301 its reverse (103200301311), we get a palindrome (216303303612).

The spelling of 113103002301 in words is "one hundred thirteen billion, one hundred three million, two thousand, three hundred one".

Divisors: 1 3 59 97 177 291 5723 17169 6587629 19762887 388670111 639000013 1166010333 1917000039 37701000767 113103002301