Base | Representation |
---|---|
bin | 1010010010010110001010… |
… | …1010001101010101101111 |
3 | 1111001020212112121100102221 |
4 | 2210211202222031111233 |
5 | 2440302000323402343 |
6 | 40015514301500211 |
7 | 2245066610536441 |
oct | 244454252152557 |
9 | 44036775540387 |
10 | 11310304122223 |
11 | 36707448aa7a7 |
12 | 1328019b71667 |
13 | 640731c522b2 |
14 | 2b15c8da4491 |
15 | 14931879b5ed |
hex | a4962a8d56f |
11310304122223 has 2 divisors, whose sum is σ = 11310304122224. Its totient is φ = 11310304122222.
The previous prime is 11310304122119. The next prime is 11310304122233. The reversal of 11310304122223 is 32222140301311.
11310304122223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (32222140301311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11310304122223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310304122233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655152061111 + 5655152061112.
It is an arithmetic number, because the mean of its divisors is an integer number (5655152061112).
Almost surely, 211310304122223 is an apocalyptic number.
11310304122223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310304122223 is an equidigital number, since it uses as much as digits as its factorization.
11310304122223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11310304122223 its reverse (32222140301311), we get a palindrome (43532444423534).
The spelling of 11310304122223 in words is "eleven trillion, three hundred ten billion, three hundred four million, one hundred twenty-two thousand, two hundred twenty-three".
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