113103101112131 has 4 divisors (see below), whose sum is σ = 121803339659232. Its totient is φ = 104402862565032.

The previous prime is 113103101112103. The next prime is 113103101112137. The reversal of 113103101112131 is 131211101301311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113103101112131 is a prime.

It is a super-2 number, since 2×113103101112131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113103101112137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4350119273531 + ... + 4350119273556.

It is an arithmetic number, because the mean of its divisors is an integer number (30450834914808).

Almost surely, 2^{113103101112131} is an apocalyptic number.

113103101112131 is a deficient number, since it is larger than the sum of its proper divisors (8700238547101).

113103101112131 is an equidigital number, since it uses as much as digits as its factorization.

113103101112131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8700238547100.

The product of its (nonzero) digits is 54, while the sum is 20.

Adding to 113103101112131 its reverse (131211101301311), we get a palindrome (244314202413442).

The spelling of 113103101112131 in words is "one hundred thirteen trillion, one hundred three billion, one hundred one million, one hundred twelve thousand, one hundred thirty-one".