Base | Representation |
---|---|
bin | 110100101010101111… |
… | …0001101101010010101 |
3 | 101210221100111111001021 |
4 | 1221111132031222111 |
5 | 3323113400231313 |
6 | 123543040401141 |
7 | 11112541525261 |
oct | 1512536155225 |
9 | 353840444037 |
10 | 113103133333 |
11 | 43a6a852113 |
12 | 19b060161b1 |
13 | a886381188 |
14 | 568d3950a1 |
15 | 2e1e75e78d |
hex | 1a5578da95 |
113103133333 has 2 divisors, whose sum is σ = 113103133334. Its totient is φ = 113103133332.
The previous prime is 113103133321. The next prime is 113103133439. The reversal of 113103133333 is 333331301311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 110956942404 + 2146190929 = 333102^2 + 46327^2 .
It is a cyclic number.
It is not a de Polignac number, because 113103133333 - 213 = 113103125141 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113103133298 and 113103133307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113103173333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56551566666 + 56551566667.
It is an arithmetic number, because the mean of its divisors is an integer number (56551566667).
Almost surely, 2113103133333 is an apocalyptic number.
It is an amenable number.
113103133333 is a deficient number, since it is larger than the sum of its proper divisors (1).
113103133333 is an equidigital number, since it uses as much as digits as its factorization.
113103133333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2187, while the sum is 25.
Adding to 113103133333 its reverse (333331301311), we get a palindrome (446434434644).
The spelling of 113103133333 in words is "one hundred thirteen billion, one hundred three million, one hundred thirty-three thousand, three hundred thirty-three".
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