Base | Representation |
---|---|
bin | 10101000100010010… |
… | …11100100110010111 |
3 | 1002012020100210021121 |
4 | 22202021130212113 |
5 | 141130420220043 |
6 | 5110151224411 |
7 | 550165063642 |
oct | 124211344627 |
9 | 32166323247 |
10 | 11310320023 |
11 | 4884420922 |
12 | 2237978107 |
13 | 10b32c9872 |
14 | 7941aca59 |
15 | 462e3aded |
hex | 2a225c997 |
11310320023 has 4 divisors (see below), whose sum is σ = 11675169088. Its totient is φ = 10945470960.
The previous prime is 11310320003. The next prime is 11310320039. The reversal of 11310320023 is 32002301311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32002301311 = 50263 ⋅636697.
It is a cyclic number.
It is not a de Polignac number, because 11310320023 - 25 = 11310319991 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11310319979 and 11310320006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11310320003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182424486 + ... + 182424547.
It is an arithmetic number, because the mean of its divisors is an integer number (2918792272).
Almost surely, 211310320023 is an apocalyptic number.
11310320023 is a deficient number, since it is larger than the sum of its proper divisors (364849065).
11310320023 is an equidigital number, since it uses as much as digits as its factorization.
11310320023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 364849064.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 11310320023 its reverse (32002301311), we get a palindrome (43312621334).
The spelling of 11310320023 in words is "eleven billion, three hundred ten million, three hundred twenty thousand, twenty-three".
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