Base | Representation |
---|---|
bin | 1010010010010110001110… |
… | …1111001110000110110111 |
3 | 1111001020220210122110201221 |
4 | 2210211203233032012313 |
5 | 2440302014441311203 |
6 | 40015520145331211 |
7 | 2245100220365221 |
oct | 244454357160667 |
9 | 44036823573657 |
10 | 11310322213303 |
11 | 3670754036903 |
12 | 1328024036b07 |
13 | 640735917889 |
14 | 2b15cb553411 |
15 | 14931a171abd |
hex | a4963bce1b7 |
11310322213303 has 4 divisors (see below), whose sum is σ = 11312040852648. Its totient is φ = 11308603573960.
The previous prime is 11310322213279. The next prime is 11310322213313. The reversal of 11310322213303 is 30331222301311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11310322213303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11310322213313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 859309801 + ... + 859322962.
It is an arithmetic number, because the mean of its divisors is an integer number (2828010213162).
Almost surely, 211310322213303 is an apocalyptic number.
11310322213303 is a deficient number, since it is larger than the sum of its proper divisors (1718639345).
11310322213303 is an equidigital number, since it uses as much as digits as its factorization.
11310322213303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1718639344.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 11310322213303 its reverse (30331222301311), we get a palindrome (41641544514614).
The spelling of 11310322213303 in words is "eleven trillion, three hundred ten billion, three hundred twenty-two million, two hundred thirteen thousand, three hundred three".
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