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113103331555 = 522620666311
BaseRepresentation
bin110100101010101111…
…0111110000011100011
3101210221100212112221211
41221111132332003203
53323113423102210
6123543044530551
711112543312214
oct1512536760343
9353840775854
10113103331555
1143a6a978035
1219b060b0a57
13a886420476
14568d40740b
152e1e79d38a
hex1a557be0e3

113103331555 has 4 divisors (see below), whose sum is σ = 135723997872. Its totient is φ = 90482665240.

The previous prime is 113103331543. The next prime is 113103331573. The reversal of 113103331555 is 555133301311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 555133301311 = 663783642203.

It is a de Polignac number, because none of the positive numbers 2k-113103331555 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11310333151 + ... + 11310333160.

It is an arithmetic number, because the mean of its divisors is an integer number (33930999468).

Almost surely, 2113103331555 is an apocalyptic number.

113103331555 is a deficient number, since it is larger than the sum of its proper divisors (22620666317).

113103331555 is an equidigital number, since it uses as much as digits as its factorization.

113103331555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22620666316.

The product of its (nonzero) digits is 10125, while the sum is 31.

Adding to 113103331555 its reverse (555133301311), we get a palindrome (668236632866).

The spelling of 113103331555 in words is "one hundred thirteen billion, one hundred three million, three hundred thirty-one thousand, five hundred fifty-five".

Divisors: 1 5 22620666311 113103331555