Base | Representation |
---|---|
bin | 10000011101010110111… |
… | …001100010000100111101 |
3 | 11000010101201121122001221 |
4 | 100131112321202010331 |
5 | 122012324241234323 |
6 | 2223331234433341 |
7 | 144500041051066 |
oct | 20352671420475 |
9 | 4003351548057 |
10 | 1131034321213 |
11 | 3a673a42a945 |
12 | 163251132851 |
13 | 8286b536354 |
14 | 3ca5703556d |
15 | 1e64a2da55d |
hex | 10756e6213d |
1131034321213 has 2 divisors, whose sum is σ = 1131034321214. Its totient is φ = 1131034321212.
The previous prime is 1131034321199. The next prime is 1131034321229. The reversal of 1131034321213 is 3121234301311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 610057847844 + 520976473369 = 781062^2 + 721787^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131034321213 - 229 = 1130497450301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131034321913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565517160606 + 565517160607.
It is an arithmetic number, because the mean of its divisors is an integer number (565517160607).
Almost surely, 21131034321213 is an apocalyptic number.
It is an amenable number.
1131034321213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131034321213 is an equidigital number, since it uses as much as digits as its factorization.
1131034321213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1131034321213 its reverse (3121234301311), we get a palindrome (4252268622524).
The spelling of 1131034321213 in words is "one trillion, one hundred thirty-one billion, thirty-four million, three hundred twenty-one thousand, two hundred thirteen".
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