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1131034321213 is a prime number
BaseRepresentation
bin10000011101010110111…
…001100010000100111101
311000010101201121122001221
4100131112321202010331
5122012324241234323
62223331234433341
7144500041051066
oct20352671420475
94003351548057
101131034321213
113a673a42a945
12163251132851
138286b536354
143ca5703556d
151e64a2da55d
hex10756e6213d

1131034321213 has 2 divisors, whose sum is σ = 1131034321214. Its totient is φ = 1131034321212.

The previous prime is 1131034321199. The next prime is 1131034321229. The reversal of 1131034321213 is 3121234301311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 610057847844 + 520976473369 = 781062^2 + 721787^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131034321213 - 229 = 1130497450301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131034321913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565517160606 + 565517160607.

It is an arithmetic number, because the mean of its divisors is an integer number (565517160607).

Almost surely, 21131034321213 is an apocalyptic number.

It is an amenable number.

1131034321213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131034321213 is an equidigital number, since it uses as much as digits as its factorization.

1131034321213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1131034321213 its reverse (3121234301311), we get a palindrome (4252268622524).

The spelling of 1131034321213 in words is "one trillion, one hundred thirty-one billion, thirty-four million, three hundred twenty-one thousand, two hundred thirteen".