Base | Representation |
---|---|
bin | 10000011101010111010… |
… | …000110011010011111001 |
3 | 11000010102011002112120011 |
4 | 100131113100303103321 |
5 | 122012332321433423 |
6 | 2223332013301521 |
7 | 144500143645051 |
oct | 20352720632371 |
9 | 4003364075504 |
10 | 1131040421113 |
11 | 3a6742916889 |
12 | 1632531948a1 |
13 | 8286c890965 |
14 | 3ca57b82561 |
15 | 1e64aae2b0d |
hex | 107574334f9 |
1131040421113 has 2 divisors, whose sum is σ = 1131040421114. Its totient is φ = 1131040421112.
The previous prime is 1131040421087. The next prime is 1131040421129. The reversal of 1131040421113 is 3111240401311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1074307374144 + 56733046969 = 1036488^2 + 238187^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131040421113 - 25 = 1131040421081 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131040421513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565520210556 + 565520210557.
It is an arithmetic number, because the mean of its divisors is an integer number (565520210557).
Almost surely, 21131040421113 is an apocalyptic number.
It is an amenable number.
1131040421113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131040421113 is an equidigital number, since it uses as much as digits as its factorization.
1131040421113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 1131040421113 its reverse (3111240401311), we get a palindrome (4242280822424).
The spelling of 1131040421113 in words is "one trillion, one hundred thirty-one billion, forty million, four hundred twenty-one thousand, one hundred thirteen".
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