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1131040421113 is a prime number
BaseRepresentation
bin10000011101010111010…
…000110011010011111001
311000010102011002112120011
4100131113100303103321
5122012332321433423
62223332013301521
7144500143645051
oct20352720632371
94003364075504
101131040421113
113a6742916889
121632531948a1
138286c890965
143ca57b82561
151e64aae2b0d
hex107574334f9

1131040421113 has 2 divisors, whose sum is σ = 1131040421114. Its totient is φ = 1131040421112.

The previous prime is 1131040421087. The next prime is 1131040421129. The reversal of 1131040421113 is 3111240401311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1074307374144 + 56733046969 = 1036488^2 + 238187^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131040421113 - 25 = 1131040421081 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131040421513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565520210556 + 565520210557.

It is an arithmetic number, because the mean of its divisors is an integer number (565520210557).

Almost surely, 21131040421113 is an apocalyptic number.

It is an amenable number.

1131040421113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131040421113 is an equidigital number, since it uses as much as digits as its factorization.

1131040421113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 1131040421113 its reverse (3111240401311), we get a palindrome (4242280822424).

The spelling of 1131040421113 in words is "one trillion, one hundred thirty-one billion, forty million, four hundred twenty-one thousand, one hundred thirteen".