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113104113212471 is a prime number
BaseRepresentation
bin11001101101111000011010…
…011111011001110000110111
3112211110122111010012020120112
4121231320122133121300313
5104311044210440244341
61040315151242453235
732552334235500353
oct3155703237316067
9484418433166515
10113104113212471
1133047204321417
121082840280421b
134b15897820b14
141dd03a827c463
15d1216e32aaeb
hex66de1a7d9c37

113104113212471 has 2 divisors, whose sum is σ = 113104113212472. Its totient is φ = 113104113212470.

The previous prime is 113104113212459. The next prime is 113104113212507. The reversal of 113104113212471 is 174212311401311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113104113212471 - 218 = 113104112950327 is a prime.

It is a super-3 number, since 3×1131041132124713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113104113202471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56552056606235 + 56552056606236.

It is an arithmetic number, because the mean of its divisors is an integer number (56552056606236).

Almost surely, 2113104113212471 is an apocalyptic number.

113104113212471 is a deficient number, since it is larger than the sum of its proper divisors (1).

113104113212471 is an equidigital number, since it uses as much as digits as its factorization.

113104113212471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 32.

Adding to 113104113212471 its reverse (174212311401311), we get a palindrome (287316424613782).

The spelling of 113104113212471 in words is "one hundred thirteen trillion, one hundred four billion, one hundred thirteen million, two hundred twelve thousand, four hundred seventy-one".