Base | Representation |
---|---|
bin | 10101000100010011… |
… | …10111011111001001 |
3 | 1002012020120101100111 |
4 | 22202021313133021 |
5 | 141130432231103 |
6 | 5110153434321 |
7 | 550166033011 |
oct | 124211673711 |
9 | 32166511314 |
10 | 11310430153 |
11 | 4884496640 |
12 | 2237a0b9a1 |
13 | 10b3337a29 |
14 | 7941dac41 |
15 | 462e5d86d |
hex | 2a22777c9 |
11310430153 has 4 divisors (see below), whose sum is σ = 12338651088. Its totient is φ = 10282209220.
The previous prime is 11310430151. The next prime is 11310430163. The reversal of 11310430153 is 35103401311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11310430153 - 21 = 11310430151 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11310430151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514110451 + ... + 514110472.
It is an arithmetic number, because the mean of its divisors is an integer number (3084662772).
Almost surely, 211310430153 is an apocalyptic number.
It is an amenable number.
11310430153 is a deficient number, since it is larger than the sum of its proper divisors (1028220935).
11310430153 is a wasteful number, since it uses less digits than its factorization.
11310430153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1028220934.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 11310430153 its reverse (35103401311), we get a palindrome (46413831464).
The spelling of 11310430153 in words is "eleven billion, three hundred ten million, four hundred thirty thousand, one hundred fifty-three".
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