Base | Representation |
---|---|
bin | 10101000100010011… |
… | …11001010001101001 |
3 | 1002012020120202101220 |
4 | 22202021321101221 |
5 | 141130432444411 |
6 | 5110153532253 |
7 | 550166063250 |
oct | 124211712151 |
9 | 32166522356 |
10 | 11310437481 |
11 | 48844a10a2 |
12 | 2237a14089 |
13 | 10b333b175 |
14 | 7941dd797 |
15 | 462e60b06 |
hex | 2a2279469 |
11310437481 has 32 divisors (see below), whose sum is σ = 17374448640. Its totient is φ = 6410954304.
The previous prime is 11310437449. The next prime is 11310437483. The reversal of 11310437481 is 18473401311.
It is a happy number.
It is not a de Polignac number, because 11310437481 - 25 = 11310437449 is a prime.
It is a super-2 number, since 2×113104374812 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11310437483) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1924215 + ... + 1930083.
It is an arithmetic number, because the mean of its divisors is an integer number (542951520).
Almost surely, 211310437481 is an apocalyptic number.
It is an amenable number.
11310437481 is a deficient number, since it is larger than the sum of its proper divisors (6064011159).
11310437481 is a wasteful number, since it uses less digits than its factorization.
11310437481 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6605.
The product of its (nonzero) digits is 8064, while the sum is 33.
Adding to 11310437481 its reverse (18473401311), we get a palindrome (29783838792).
The spelling of 11310437481 in words is "eleven billion, three hundred ten million, four hundred thirty-seven thousand, four hundred eighty-one".
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