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113104550245 = 5297057110533
BaseRepresentation
bin110100101010110001…
…1100111100101100101
3101210221110011110200111
41221111203213211211
53323114231101440
6123543131013021
711112556546231
oct1512543474545
9353843143614
10113104550245
1143a7062a715
1219b0659a171
13a88675909b
14568d6435c1
152e1e93e4ea
hex1a558e7965

113104550245 has 16 divisors (see below), whose sum is σ = 140426814960. Its totient is φ = 87350344704.

The previous prime is 113104550239. The next prime is 113104550261. The reversal of 113104550245 is 542055401311.

It can be written as a sum of positive squares in 8 ways, for example, as 18693999076 + 94410551169 = 136726^2 + 307263^2 .

It is a cyclic number.

It is not a de Polignac number, because 113104550245 - 25 = 113104550213 is a prime.

It is a super-2 number, since 2×1131045502452 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 967999 + ... + 1078531.

It is an arithmetic number, because the mean of its divisors is an integer number (8776675935).

Almost surely, 2113104550245 is an apocalyptic number.

It is an amenable number.

113104550245 is a deficient number, since it is larger than the sum of its proper divisors (27322264715).

113104550245 is a wasteful number, since it uses less digits than its factorization.

113104550245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117624.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 113104550245 its reverse (542055401311), we get a palindrome (655159951556).

The spelling of 113104550245 in words is "one hundred thirteen billion, one hundred four million, five hundred fifty thousand, two hundred forty-five".

Divisors: 1 5 29 145 7057 35285 110533 204653 552665 1023265 3205457 16027285 780031381 3900156905 22620910049 113104550245