Base | Representation |
---|---|
bin | 110100101010110001… |
… | …1100111100101100101 |
3 | 101210221110011110200111 |
4 | 1221111203213211211 |
5 | 3323114231101440 |
6 | 123543131013021 |
7 | 11112556546231 |
oct | 1512543474545 |
9 | 353843143614 |
10 | 113104550245 |
11 | 43a7062a715 |
12 | 19b0659a171 |
13 | a88675909b |
14 | 568d6435c1 |
15 | 2e1e93e4ea |
hex | 1a558e7965 |
113104550245 has 16 divisors (see below), whose sum is σ = 140426814960. Its totient is φ = 87350344704.
The previous prime is 113104550239. The next prime is 113104550261. The reversal of 113104550245 is 542055401311.
It can be written as a sum of positive squares in 8 ways, for example, as 18693999076 + 94410551169 = 136726^2 + 307263^2 .
It is a cyclic number.
It is not a de Polignac number, because 113104550245 - 25 = 113104550213 is a prime.
It is a super-2 number, since 2×1131045502452 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 967999 + ... + 1078531.
It is an arithmetic number, because the mean of its divisors is an integer number (8776675935).
Almost surely, 2113104550245 is an apocalyptic number.
It is an amenable number.
113104550245 is a deficient number, since it is larger than the sum of its proper divisors (27322264715).
113104550245 is a wasteful number, since it uses less digits than its factorization.
113104550245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117624.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 113104550245 its reverse (542055401311), we get a palindrome (655159951556).
The spelling of 113104550245 in words is "one hundred thirteen billion, one hundred four million, five hundred fifty thousand, two hundred forty-five".
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