1131045583 has 2 divisors, whose sum is σ = 1131045584. Its totient is φ = 1131045582.

The previous prime is 1131045551. The next prime is 1131045593. The reversal of 1131045583 is 3855401311.

It is a strong prime.

It is an emirp because it is prime and its reverse (3855401311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131045583 - 2⁵ = 1131045551 is a prime.

It is a super-2 number, since 2×1131045583² = 2558528221647619778, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131045593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565522791 + 565522792.

It is an arithmetic number, because the mean of its divisors is an integer number (565522792).

Almost surely, 2^1131045583 is an apocalyptic number.

1131045583 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131045583 is an equidigital number, since it uses as much as digits as its factorization.

1131045583 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 31.

The square root of 1131045583 is about 33631.0211412024. The cubic root of 1131045583 is about 1041.9015945546.

Adding to 1131045583 its reverse (3855401311), we get a palindrome (4986446894).

The spelling of 1131045583 in words is "one billion, one hundred thirty-one million, forty-five thousand, five hundred eighty-three".