113110021213333 has 2 divisors, whose sum is σ = 113110021213334. Its totient is φ = 113110021213332.

The previous prime is 113110021213327. The next prime is 113110021213361. The reversal of 113110021213333 is 333312120011311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75470606013924 + 37639415199409 = 8687382^2 + 6135097^2 .

It is a cyclic number.

It is not a de Polignac number, because 113110021213333 - 2²¹ = 113110019116181 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113110021213298 and 113110021213307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113110021213933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555010606666 + 56555010606667.

It is an arithmetic number, because the mean of its divisors is an integer number (56555010606667).

Almost surely, 2^{113110021213333} is an apocalyptic number.

It is an amenable number.

113110021213333 is a deficient number, since it is larger than the sum of its proper divisors (1).

113110021213333 is an equidigital number, since it uses as much as digits as its factorization.

113110021213333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 113110021213333 its reverse (333312120011311), we get a palindrome (446422141224644).

The spelling of 113110021213333 in words is "one hundred thirteen trillion, one hundred ten billion, twenty-one million, two hundred thirteen thousand, three hundred thirty-three".