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11311021103003 is a prime number
BaseRepresentation
bin1010010010011000110101…
…1001010001011110011011
31111001022201111201202011122
42210212031121101132123
52440304432400244003
640020113353115455
72245123435013426
oct244461531213633
944038644652148
1011311021103003
113670a82597aa6
12132819a0b8b8b
1364081765878b
142b16562bc9bd
1514935b6c5238
hexa498d65179b

11311021103003 has 2 divisors, whose sum is σ = 11311021103004. Its totient is φ = 11311021103002.

The previous prime is 11311021102981. The next prime is 11311021103033. The reversal of 11311021103003 is 30030112011311.

11311021103003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11311021103003 - 220 = 11311020054427 is a prime.

It is not a weakly prime, because it can be changed into another prime (11311021103033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655510551501 + 5655510551502.

It is an arithmetic number, because the mean of its divisors is an integer number (5655510551502).

Almost surely, 211311021103003 is an apocalyptic number.

11311021103003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311021103003 is an equidigital number, since it uses as much as digits as its factorization.

11311021103003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11311021103003 its reverse (30030112011311), we get a palindrome (41341133114314).

The spelling of 11311021103003 in words is "eleven trillion, three hundred eleven billion, twenty-one million, one hundred three thousand, three".