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1131102133303 = 6118542657923
BaseRepresentation
bin10000011101011010111…
…100001101110000110111
311000010120110012211202211
4100131122330031300313
5122012444121231203
62223342100114251
7144501523333012
oct20353274156067
94003513184684
101131102133303
113a677473709a
1216326b995987
138287c5ba04c
143ca62048379
151e651232c6d
hex1075af0dc37

1131102133303 has 4 divisors (see below), whose sum is σ = 1149644791288. Its totient is φ = 1112559475320.

The previous prime is 1131102133279. The next prime is 1131102133363. The reversal of 1131102133303 is 3033312011311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131102133303 - 217 = 1131102002231 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131102133363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9271328901 + ... + 9271329022.

It is an arithmetic number, because the mean of its divisors is an integer number (287411197822).

Almost surely, 21131102133303 is an apocalyptic number.

1131102133303 is a deficient number, since it is larger than the sum of its proper divisors (18542657985).

1131102133303 is an equidigital number, since it uses as much as digits as its factorization.

1131102133303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18542657984.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 1131102133303 its reverse (3033312011311), we get a palindrome (4164414144614).

The spelling of 1131102133303 in words is "one trillion, one hundred thirty-one billion, one hundred two million, one hundred thirty-three thousand, three hundred three".

Divisors: 1 61 18542657923 1131102133303