Base | Representation |
---|---|
bin | 11001101101111110001100… |
… | …000001101110100001011100 |
3 | 112211111020111012012020110200 |
4 | 121231332030001232201130 |
5 | 104311144410112044400 |
6 | 1040322054353503500 |
7 | 32552644000031610 |
oct | 3155761401564134 |
9 | 484436435166420 |
10 | 113110313003100 |
11 | 330498a5a01926 |
12 | 10829652b71b90 |
13 | 4b163450cc79a |
14 | 1dd07d5817340 |
15 | d123d377ab00 |
hex | 66df8c06e85c |
113110313003100 has 216 divisors, whose sum is σ = 405193984654368. Its totient is φ = 25853294016000.
The previous prime is 113110313003081. The next prime is 113110313003119. The reversal of 113110313003100 is 1300313011311.
113110313003100 is a `hidden beast` number, since 1 + 1 + 31 + 10 + 313 + 0 + 0 + 310 + 0 = 666.
113110313003100 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (113110313003081) and next prime (113110313003119).
It is a super-2 number, since 2×1131103130031002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 408737982 + ... + 409014618.
Almost surely, 2113110313003100 is an apocalyptic number.
113110313003100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113110313003100 is an abundant number, since it is smaller than the sum of its proper divisors (292083671651268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113110313003100 is a wasteful number, since it uses less digits than its factorization.
113110313003100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 341565 (or 341555 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 18.
Adding to 113110313003100 its reverse (1300313011311), we get a palindrome (114410626014411).
The spelling of 113110313003100 in words is "one hundred thirteen trillion, one hundred ten billion, three hundred thirteen million, three thousand, one hundred".
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