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113110320113 = 719379833821
BaseRepresentation
bin110100101010111100…
…1101000001111110001
3101210221212000121110022
41221111321220033301
53323122220220423
6123543454413225
711112656600060
oct1512571501761
9353855017408
10113110320113
1143a739106aa
1219b08501215
13a8879c93cb
1456903061d7
152e201cddc8
hex1a55e683f1

113110320113 has 8 divisors (see below), whose sum is σ = 129275762880. Its totient is φ = 96946583760.

The previous prime is 113110320109. The next prime is 113110320119. The reversal of 113110320113 is 311023011311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113110320113 - 22 = 113110320109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113110320091 and 113110320100.

It is not an unprimeable number, because it can be changed into a prime (113110320119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 281258 + ... + 552563.

It is an arithmetic number, because the mean of its divisors is an integer number (16159470360).

Almost surely, 2113110320113 is an apocalyptic number.

It is an amenable number.

113110320113 is a deficient number, since it is larger than the sum of its proper divisors (16165442767).

113110320113 is an equidigital number, since it uses as much as digits as its factorization.

113110320113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 853207.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 113110320113 its reverse (311023011311), we get a palindrome (424133331424).

The spelling of 113110320113 in words is "one hundred thirteen billion, one hundred ten million, three hundred twenty thousand, one hundred thirteen".

Divisors: 1 7 19379 135653 833821 5836747 16158617159 113110320113