Base | Representation |
---|---|
bin | 11001101101111110001100… |
… | …100101010011100110010011 |
3 | 112211111020111211202002120112 |
4 | 121231332030211103212103 |
5 | 104311144420004030003 |
6 | 1040322055325431535 |
7 | 32552644142226005 |
oct | 3155761445234623 |
9 | 484436454662515 |
10 | 113110322330003 |
11 | 330499001a2309 |
12 | 1082965610b5ab |
13 | 4b16347016b6b |
14 | 1dd07d6b64375 |
15 | d123d44be3d8 |
hex | 66df8c953993 |
113110322330003 has 4 divisors (see below), whose sum is σ = 113112157079208. Its totient is φ = 113108487580800.
The previous prime is 113110322329943. The next prime is 113110322330023. The reversal of 113110322330003 is 300033223011311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113110322330003 - 28 = 113110322329747 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113110322330023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 917282126 + ... + 917405427.
It is an arithmetic number, because the mean of its divisors is an integer number (28278039269802).
Almost surely, 2113110322330003 is an apocalyptic number.
113110322330003 is a deficient number, since it is larger than the sum of its proper divisors (1834749205).
113110322330003 is an equidigital number, since it uses as much as digits as its factorization.
113110322330003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1834749204.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 113110322330003 its reverse (300033223011311), we get a palindrome (413143545341314).
The spelling of 113110322330003 in words is "one hundred thirteen trillion, one hundred ten billion, three hundred twenty-two million, three hundred thirty thousand, three".
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